A circle is a set of all points in a plane that are equidistant from a fixed point called the center. The constant distance is called the radius.

Unlike polygons, a circle has no angles and no sides, but it carries some of the most powerful geometric properties you'll encounter.


Key Terminology

TermDefinition
Radius (r)Distance from the center to any point on the circle
Diameter (d)A chord that passes through the center; longest chord d=2rd = 2r
Circumference (C)Perimeter of the circle C=2πrC = 2\pi r
AreaSpace enclosed A=πr2A = \pi r^2
ChordA line segment with endpoints on the circle
ArcA part of the circle's circumference
SectorPortion of a circle enclosed by two radii and the arc
SegmentRegion between a chord and the corresponding arc
Central AngleAngle subtended at the center by an arc
Minor/Major ArcSmaller/larger of the two arcs subtended by a chord

Important Formulas

1. Circumference

C=2πr=πdC = 2\pi r = \pi d

2. Area

A=πr2A = \pi r^2

3. Length of an Arc (central angle θ\theta^\circ)

Length=θ360×2πr\text{Length} = \frac{\theta}{360} \times 2\pi r

4. Area of a Sector

Area=θ360×πr2\text{Area} = \frac{\theta}{360} \times \pi r^2

5. Area of a Segment

Segment Area=Sector AreaArea of Triangle (formed by radii)\text{Segment Area} = \text{Sector Area} - \text{Area of Triangle (formed by radii)}

Geometric Properties and Theorems

1. Angle at the Centre vs. Angle at the Circle

  • The angle subtended at the center is twice the angle subtended at the circumference:
AOB=2ACB\angle AOB = 2 \cdot \angle ACB

2. Angle in a Semicircle

  • Any angle inscribed in a semicircle is a right angle (90°).

3. Cyclic Quadrilateral

  • All vertices lie on a circle
  • Sum of opposite angles = 180°

4. Perpendicular from Center to a Chord

  • Always bisects the chord.

5. Equal Chords

  • Subtend equal arcs and are equidistant from the center.

6. Tangents

  • A tangent is a line that touches the circle at exactly one point.
  • Always perpendicular to the radius at the point of contact.
  • From an external point, lengths of tangents to the circle are equal.

Special Cases and Advanced Formulas

1. Area of Ring (Annulus)

A ring formed between two concentric circles with radii RR and rr:

Area=π(R2r2)\text{Area} = \pi(R^2 - r^2)

2. Number of Tangents from a Point

  • From a point outside the circle: 2 tangents
  • From a point on the circle: 1 tangent
  • From a point inside: No tangent

Visual Explanations

Circle Components Diagram:

            B
           / \
        r /   \ r
         /     \
        O-------A
            d
  • OO = Center
  • ABAB = Diameter
  • rr = Radius
  • Circumference: Full boundary
  • Area: Entire region enclosed

Conceptual Tips and Common Mistakes

MistakeTip
Using radius instead of diameter (or vice versa)Always confirm what's given — d=2rd = 2r
Confusing arc length with sector areaArc = length (1D), Sector = area (2D)
Forgetting unit consistencyKeep all values in same units: cm, m, etc.
Misusing the tangent propertyTangents from an external point are equal and perpendicular to radius

Shortcuts and Tricks

  • Semicircle implies a 90° angle at the circumference.

  • Use Pythagoras when tangents or radii create right triangles.

  • Memorize that the longest chord = diameter.

  • For rapid MCQ solving:

    • Angle subtended by diameter = 90°
    • Angle subtended by chord at center = 2×2 \times angle at arc

Examples

Example 1:

A circle has radius 7 cm. Find circumference and area.

C=2πr=2×π×7=44 cmA=πr2=π×49154 cm2C = 2\pi r = 2 \times \pi \times 7 = 44 \text{ cm} \\ A = \pi r^2 = \pi \times 49 \approx 154 \text{ cm}^2

Example 2:

Find the length of an arc that subtends 60° in a circle of radius 6 cm.

Arc Length=60360×2π×6=16×12π=2π6.28 cm\text{Arc Length} = \frac{60}{360} \times 2\pi \times 6 = \frac{1}{6} \times 12\pi = 2\pi \approx 6.28 \text{ cm}

Example 3:

Two tangents are drawn from a point 10 cm away from the center to a circle of radius 6 cm. Find the length of each tangent.

Use Pythagoras in the right triangle:

l=10262=10036=64=8 cml = \sqrt{10^2 - 6^2} = \sqrt{100 - 36} = \sqrt{64} = 8 \text{ cm}