Probability quantifies the chance or likelihood of an event occurring. It is a number between 0 and 1 (or 0% to 100%), where:

  • 0 means the event never occurs
  • 1 means the event always occurs
  • Values between 0 and 1 show the degree of likelihood

Example: Tossing a fair coin has two equally likely outcomes: Heads or Tails. Probability of getting Heads = 12=0.5\frac{1}{2} = 0.5.


2. Key Formulas & Shortcuts

Let:

  • SS = Sample space (total possible outcomes)
  • EE = Event (favorable outcomes)
  • n(S)n(S) = Number of elements in sample space
  • n(E)n(E) = Number of elements favorable to event

A. Probability of an event EE:

P(E)=n(E)n(S)P(E) = \frac{n(E)}{n(S)}

B. Probability of complement of EE (event not happening):

P(E)=1P(E)P(E') = 1 - P(E)

C. Addition Rule (for two events AA and BB):

  • If mutually exclusive (cannot occur together):
P(AB)=P(A)+P(B)P(A \cup B) = P(A) + P(B)
  • If not mutually exclusive:
P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B)

D. Multiplication Rule:

  • For independent events AA and BB:
P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B)
  • For dependent events, use conditional probability (covered below).

E. Conditional Probability:

P(AB)=P(AB)P(B)P(A|B) = \frac{P(A \cap B)}{P(B)}

Probability of AA given BB has occurred.


F. Probability of "At least one":

P(at least one)=1P(none)P(\text{at least one}) = 1 - P(\text{none})

G. Total Probability (Law of Total Probability):

If B1,B2,...,BnB_1, B_2, ..., B_n form a partition of the sample space,

P(A)=i=1nP(ABi)P(Bi)P(A) = \sum_{i=1}^n P(A|B_i) P(B_i)

3. Conceptual Tips & Common Mistakes

  • Always check if outcomes are equally likely before using simple ratio formula.

  • Don't confuse union and intersection:

    • Union ABA \cup B = event AA or BB or both.
    • Intersection ABA \cap B = event AA and BB both.
  • Conditional probability requires dividing by the probability of the given condition/event.

  • For "at least one" problems, using complement saves time and effort.

  • Make sure events are independent before applying multiplication rule directly.

  • Draw sample spaces or tree diagrams for complex problems.


5. Solved Examples

Example 1: Basic Probability

Q: A die is rolled once. What is the probability of getting an even number?

A:

  • Sample space, n(S)=6n(S) = 6 (1, 2, 3, 4, 5, 6)
  • Favorable outcomes, n(E)=3n(E) = 3 (2, 4, 6)
P(E)=36=12P(E) = \frac{3}{6} = \frac{1}{2}

Example 2: Complement Rule

Q: Probability of not getting a 6 in one roll of a die?

A:

P(not 6)=1P(6)=116=56P(\text{not }6) = 1 - P(6) = 1 - \frac{1}{6} = \frac{5}{6}

Example 3: Union of Two Events

Q: From a deck of cards, probability of drawing a card that is a King or a Heart?

A:

  • P(King)=452P(King) = \frac{4}{52}
  • P(Heart)=1352P(Heart) = \frac{13}{52}
  • P(KingHeart)=152P(King \cap Heart) = \frac{1}{52} (King of Hearts)
P(KH)=452+1352152=1652=413P(K \cup H) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52} = \frac{4}{13}

Example 4: Independent Events

Q: Two coins tossed. Probability both show heads?

A:

P(H)=12P(HH)=12×12=14P(H) = \frac{1}{2} \quad\Rightarrow\quad P(HH) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}

Example 5: Conditional Probability

Q: A bag has 3 red and 2 blue balls. One ball is drawn. Given that it is red, what is the probability that the next ball drawn is also red (without replacement)?

A:

After 1 red ball is taken, remaining balls = 4, red balls = 2

P(2nd red1st red)=24=12P(\text{2nd red} | \text{1st red}) = \frac{2}{4} = \frac{1}{2}

Example 6: At Least One

Q: Probability of getting at least one head in two tosses of a coin?

A:

P(no heads)=P(TT)=14P(\text{no heads}) = P(TT) = \frac{1}{4} P(at least one head)=114=34P(\text{at least one head}) = 1 - \frac{1}{4} = \frac{3}{4}