In village B, the number of females was what percent less than the number of males?

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Accepted Answer

Let male population = $M$ and female population = $F$. For village B:

1. Literates among males = $64\%$ of $M$ = $0.64M$.
2. Literates among females = $56\%$ of $F$ = $0.56F$.
3. Total literates = $61\%$ of total population = $0.61(M+F)$.

Set up the equation:

$0.64M + 0.56F = 0.61(M+F)$.

Simplify:

$0.64M + 0.56F = 0.61M + 0.61F$

$0.64M - 0.61M = 0.61F - 0.56F$

$0.03M = 0.05F$

So $F = \dfrac{0.03}{0.05}M = \dfrac{3}{5}M = 0.6M$.

Thus the number of females is $0.6M$, which is $40\%$ less than the number of males (since $1 - 0.6 = 0.4$).

FINAL_ANSWER: d

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