The total number of literates (male and female) in Village D was 4320. If the number of illiterate females was 320 more than the number of illiterate males, what was the male population of the village?

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Step-by-step solution:

1. From the table the overall literacy rate in Village D is 60%, and the total number of literates is 4320. So the total population $P$ is

$P=\dfrac{4320}{0.6}=7200$.

2. Let male population be $M$ and female population be $F$. Then

$M+F=7200$.

3. The female literacy rate for D is 60%, so female literates = $0.6F$ and female illiterates = $0.4F$.

4. Let male literates be $L_m$. Total literates give

$L_m+0.6F=4320\Rightarrow L_m=4320-0.6F$.

Male illiterates = $M-L_m=(7200-F)-(4320-0.6F)=2880-0.4F$.

5. We are told female illiterates exceed male illiterates by 320:

$0.4F-(2880-0.4F)=320$.

Simplify: $0.8F-2880=320\Rightarrow 0.8F=3200\Rightarrow F=4000$.

6. Therefore male population $M=7200-4000=3200$.

FINAL_ANSWER: a

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