Rutuja bought two articles - article A at Rs. X and article B at Rs. X + 50. She sold article A at 20% profit and article B at 10% loss and earned Rs.35 as profit on the whole deal. I. Profit earned by Rutuja on selling article A (in Rs.). II. Loss incurred (in Rs.) when an article which costs Rs.480 is sold at 20% loss.

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Step 1: Let cost of A be $X$ and cost of B be $X+50$.\
Selling price of A at 20% profit: $SP_A=1.2X$.\
Selling price of B at 10% loss: $SP_B=0.9(X+50)$.\
Total cost = $X+(X+50)=2X+50$. Total selling price = $1.2X+0.9(X+50)=2.1X+45$.\
Given overall profit = $35$, so
$$ (2.1X+45)-(2X+50)=35. $$
Simplify: $0.1X-5=35\Rightarrow 0.1X=40\Rightarrow X=400$.\
Step 2 (Quantity I): Profit on A = 20% of $X$ = $0.2	imes400=80$. So Quantity I = Rs. 80.\
Step 3 (Quantity II): Loss on an article costing Rs. 480 sold at 20% loss = $0.2	imes480=96$. So Quantity II = Rs. 96.\
Comparison: $80<96$, so Quantity I < Quantity II.\
FINAL_ANSWER: c

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