A shopkeeper purchased 15 kg of variety A rice at X per kg and 10 kg of variety B rice at ‘X+ 5’ per kg. The shopkeeper sold the whole quantity of variety A rice at 10% profit and that of variety B rice at 20% profit. The total selling price of variety A rice was Rs. 30 more than that of variety B rice. Had the two varieties been mixed and sold at an overall profit of 20%, what would have been the selling price (per kg)?

Question

Accepted Answer

Step-by-step solution:

1. Let the cost price of variety A be $X$ (Rs/kg). Then variety B costs $X+5$ (Rs/kg).
2. Total selling price of A at 10% profit: per kg $=1.1X$, so total $=15	imes1.1X=16.5X$.
3. Total selling price of B at 20% profit: per kg $=1.2(X+5)$, so total $=10	imes1.2(X+5)=12(X+5)=12X+60$.
4. Given: total SP of A is Rs.30 more than total SP of B, so

$16.5X=12X+60+30=12X+90$.

Solve: $16.5X-12X=4.5X=90\Rightarrow X=20$ (Rs/kg).
5. Cost totals: A costs $15	imes20=300$, B costs $10	imes25=250$, so total cost $=300+250=550$ for $15+10=25$ kg.
6. If mixed and sold at overall 20% profit, total selling price $=1.2	imes550=660$.
7. Selling price per kg $=660/25=26.4$ (Rs/kg).

FINAL_ANSWER: a

Answer

Answer

Answer

Answer