Abhay rolled a pair of die together. What is the probability that one die showed a multiple of 2 and the second die showed neither a multiple of 3 nor 2?

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Step-by-step explanation:

- Total possible ordered outcomes = $6 	imes 6 = 36$.
- Multiples of 2 on a die = $\{2,4,6\}$ → 3 outcomes.
- Numbers that are neither multiples of 2 nor 3 = $\{1,5\}$ → 2 outcomes.
- Favorable ordered outcomes = $3 	imes 2 = 6$.
- Probability = $\frac{6}{36} = \frac{1}{6}$.

Therefore the correct option is C.
FINAL_ANSWER: c

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