Statements: All registers are pens. All pens are pencils. No pencil is rubber. Conclusions I: No register is rubber. Conclusion II: All pencils are pens.

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Let R = registers, P = pens, C = pencils, and U = rubbers.

1. From the statements: all registers are pens and all pens are pencils, so
   - $R\subseteq P$ and $P\subseteq C$.
2. By transitivity, $R\subseteq C$ (every register is a pencil).
3. From "No pencil is rubber" we have $C\cap U=\varnothing$. Since $R\subseteq C$, it follows that $R\cap U=\varnothing$ as well. Therefore no register is rubber — Conclusion I follows.
4. Conclusion II asserts "All pencils are pens", i.e. $C\subseteq P$. We only have $P\subseteq C$; the reverse inclusion does not follow from the given statements, so Conclusion II does not follow.

FINAL_ANSWER: e

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