An electric iron requires a ________ fuse to prevent short circuiting.

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Step 1: Estimate typical iron power. A common electric iron is about 1000 W (often 1000–1500 W).  
Step 2: Compute operating current at mains voltage. For 1000 W at 220 V: $I=\dfrac{P}{V}=\dfrac{1000}{220}\approx4.55\ 	ext{A}$. For 1000 W at 200 V: $I=\dfrac{1000}{200}=5\ 	ext{A}$.  
Step 3: Choose the nearest standard fuse rating slightly above the normal current so it does not blow in normal use but will blow on a short circuit. From the given options, 5 A is the appropriate choice.  
FINAL_ANSWER: d

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