The molecular formula of glucose is C₆H₁₂O₆. Calculate the percentage by weight of carbon present in glucose.

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### Solution:
Molecular formula of glucose = C₆H₁₂O₆

Atomic masses: C = 12, H = 1, O = 16
Total molar mass of glucose: = (6 × 12) + (12 × 1) + (6 × 16) = 72 + 12 + 96 = 180

Mass of carbon in glucose: = 6 × 12 = 72

Percentage of carbon: = (72 / 180) × 100 = 40%

### Final Answer:
40%

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