A 50-litre mixture contains juice and water in the ratio 3:2. How much water (in litres) must be added to this mixture to change the ratio of juice to water to 3:4?

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Accepted Answer

1. The mixture is 50 L with ratio 3:2. So juice = $	frac{3}{5}	imes50=30$ L and water = 20 L.

2. Let added water be $x$. New water = $20+x$, juice = 30.

3. Set the new ratio: $\dfrac{30}{20+x}=\dfrac{3}{4}$.

4. Solve: $30	imes4=3(20+x)\Rightarrow120=60+3x\Rightarrow x=20$.

FINAL_ANSWER: d

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