A car wheel having a radius of 42 cm. What percentage of its circumference is covered in a half turn?
(Use π = 22/7)

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Accepted Answer

1. Use circumference formula: $C=2\pi r$. 
2. Substitute $\pi=22/7$ and $r=42$: $C=2	imes\frac{22}{7}	imes42=264\ 	ext{cm}$. 
3. A half turn covers $\frac{C}{2}=132\ 	ext{cm}$. 
4. Percentage = $\dfrac{132}{264}	imes100\%=50\%$. **So half the circumference is 50%.**

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