Find the number that breaks the pattern:
3, 7, 15, 31, 63, 120

Question

Accepted Answer

1. The rule is: each term is previous term times 2 plus 1, i.e. $a_{n+1}=2a_n+1$.

2. Check: $3	o7$ because $3	imes2+1=7$.

3. Then $7	o15$, $15	o31$, $31	o63$ all fit the rule.

4. Next should be $63	imes2+1=127$, but the list gives 120, so 120 breaks the pattern.

FINAL_ANSWER: d

Answer

Answer

Answer