If Earth’s radius shrinks by 1% with mass constant, surface gravitational acceleration would:

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Accepted Answer

1. Use the gravity formula: $g=\dfrac{GM}{R^2}$.

2. If radius shrinks by 1%, new radius $R'=0.99R$.

3. New gravity $g'=g/0.99^2\approx g/0.9801\approx 1.0203\,g$, about a 2% increase.

4. So surface gravity **rises by about 2%**.

FINAL_ANSWER: c

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