Let a = √5 + √7 and b = √12 + √3. Which is greater?

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Accepted Answer

1. Compute $a$: $a=\sqrt{5}+\sqrt{7}\approx2.236+2.646=4.882$.

2. Simplify $b$: $\sqrt{12}=2\sqrt{3}$ so $b=2\sqrt{3}+\sqrt{3}=3\sqrt{3}\approx3	imes1.732=5.196$.

3. Compare: $4.882<5.196$, so $a<b$.

4. Thus option **(c)** is correct.

FINAL_ANSWER: <c>

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Answer

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