If sin (90° - B) = 2/3, what is cos B?

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1. Recall the cofunction identity: $\sin(90^\circ - x)=\cos x$.  
2. Put $x=B$: $\cos B=\sin(90^\circ - B)=	frac{2}{3}$.  
3. So the value of $\cos B$ is $2/3$, which is option **(b)**.

FINAL_ANSWER: b

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