The ratio of efficiencies of workers A and B is 4:3. If A can finish a task in 18 days, in how many days will B finish the same task alone?

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Accepted Answer

1. Let the work rates be $4k$ and $3k$ for A and B.

2. A's rate $4k=\frac{1}{18}$, so $k=\frac{1}{72}$.

3. B's rate $=3k=\frac{3}{72}=\frac{1}{24}$.

4. Time for B $=\frac{1}{	ext{rate}}=24$ days.

FINAL_ANSWER: c

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