Two cyclists start from the same point on a circular track of length 900 m at 7:00 a.m. and ride in opposite directions. Their speeds are 6 km/h and 9 km/h respectively. At what time will they meet for the fourth time?

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1. Relative speed = $6+9=15	ext{ km/h}=\dfrac{15000}{3600}=\dfrac{25}{6}	ext{ m/s}.$
2. Time for one meeting = $900\div\dfrac{25}{6}=216	ext{ s}=3	ext{ min }36	ext{ s}.$
3. Fourth meeting = $4	imes216=864	ext{ s}=14	ext{ min }24	ext{ s}$ after 7:00.
4. So the time is 7:14:24 a.m.

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