If t = √6 + 3, find t² − 6√6.

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Accepted Answer

1. Square $t$: $t=(\sqrt{6}+3)$ so $t^2=(\sqrt{6}+3)^2$.
2. Expand: $t^2=6+2\cdot3\sqrt{6}+9=15+6\sqrt{6}$.
3. Subtract: $t^2-6\sqrt{6}=15$.
FINAL_ANSWER: d

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