In each of the following questions, the second group of letters is formed from the first using a specific alphabetical transformation. Apply the same pattern to the third group and find the correct option that completes the analogy. QDXM : SFYN :: UIOZ : ?

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Solution:
Given analogy:
QDXM : SFYN :: UIOZ : ?
Compare the first pair:
QDXM → SFYN
Letter-wise change:
Q → S = +2 D → F = +2 X → Y = +1 M → N = +1
So the pattern is:
First letter: +2 Second letter: +2 Third letter: +1 Fourth letter: +1
Now apply the same pattern to UIOZ:
U → W = +2 I → K = +2 O → P = +1 Z → A = +1, after Z comes A
So:
UIOZ → WKPA
Therefore, the correct answer is:
**(d) WKPA**

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