A cricketer's average score over a series of matches is 42. If she scores 138 runs in the next match, her average increases to 46. How many matches did she play before this?

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1. Let number of matches before = n. Total runs = $42n$.
2. After scoring 138, total = $42n+138$ and matches = $n+1$.
3. New average: $\frac{42n+138}{n+1}=46$. Solve: $42n+138=46n+46$.
4. So $138-46=4n\Rightarrow 92=4n\Rightarrow n=23$. **Answer: (a)**
FINAL_ANSWER: a

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