A person travels between two towns. At 60 km/h, he arrives 1.5 hours early. At 40 km/h, he arrives 1 hour late. What is the distance between the towns?

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Accepted Answer

1. Let $D$ be the distance and $t$ the scheduled time.

2. At 60 km/h he is early: $\frac{D}{60}=t-1.5$.

3. At 40 km/h he is late: $\frac{D}{40}=t+1$.

4. Subtract: $\frac{D}{40}-\frac{D}{60}=2.5\Rightarrow\frac{D}{120}=2.5\Rightarrow D=300$ km.

FINAL_ANSWER: a

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