If 4 # 3 = 19 and 6 # 5 = 41, then 8 # 7 = ?

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Accepted Answer

1. Compute difference from product: $19-4\cdot3=7$ and $41-6\cdot5=11$.
2. Notice these are the sums: $4+3=7$ and $6+5=11$.
3. So the rule is: $a\#b = a\cdot b + (a+b)$.
4. Apply it: $8\#7 = 8\cdot7 + (8+7) = 56 + 15 = 71$.

FINAL_ANSWER: c

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