Train A leaves Station X at 5:00 AM at 50 km/h. Train B leaves Station Y at 7:30 AM at 80 km/h. Both trains move towards each other. Distance = 500 km. When do they meet?

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Accepted Answer

1. Train A runs from 5:00 to 7:30, which is $2.5$ h. Distance = $50	imes2.5=125$ km.
2. Remaining distance = $500-125=375$ km when B starts.
3. Combined speed = $50+80=130$ km/h. Time to meet = $\dfrac{375}{130}=2.8846	ext{ h}=2	ext{ h }53	ext{ min}$.
4. Meeting time = 7:30 + 2:53 = **10:23 AM**.

FINAL_ANSWER: c

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