A 50-litre mixture of oil and water has 16% water. How many litres of oil must be added to make water content 10%?

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Accepted Answer

1. **Find water amount:** $0.16	imes50=8$ litres of water.

2. **Let oil added be** $x$. Total volume becomes $50+x$ litres. Water stays 8 litres.

3. **Set the fraction:** $\frac{8}{50+x}=0.10$.

4. **Solve:** $8=0.1(50+x)\Rightarrow0.1x=3\Rightarrow x=30$. So add 30 litres.

FINAL_ANSWER: d

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