A box has 4 red, 5 blue and 6 green balls. What is the probability of drawing a non-blue ball? 4

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Accepted Answer

1. Count total balls: $4+5+6=15$. 
2. Non-blue balls = red + green = $4+6=10$. 
3. Probability = $\frac{10}{15}=\frac{2}{3}$. 
4. Option (c) is $10/15$, so choose (c). 
FINAL_ANSWER: c

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