What should be subtracted from 8, 10, 11, 14 so that the remaining numbers may be proportional?

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1. Let $x$ be subtracted. New numbers: $8-x,\;10-x,\;11-x,\;14-x$.
2. For proportionality: $\dfrac{8-x}{10-x}=\dfrac{11-x}{14-x}$.
3. Cross-multiply: $(8-x)(14-x)=(10-x)(11-x)$.
4. Expand and simplify: $112-22x+x^2=110-21x+x^2\Rightarrow2-x=0$, so $x=2$.

FINAL_ANSWER: a

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