Karan borrowed money at SI: 6% for first 4 years, 8% for next 3 years, 10% beyond 7 years. Total interest after 9 years is ₹4,760. How much did he borrow?

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Solution:
Let the amount borrowed be:
$$ P $$
Simple interest for the first 4 years at 6%:
$$ \frac{P 	imes 6 	imes 4}{100} = \frac{24P}{100} $$
Simple interest for the next 3 years at 8%:
$$ \frac{P 	imes 8 	imes 3}{100} = \frac{24P}{100} $$
Simple interest for the remaining 2 years at 10%:
$$ \frac{P 	imes 10 	imes 2}{100} = \frac{20P}{100} $$
Total interest after 9 years:
$$ \frac{24P}{100} + \frac{24P}{100} + \frac{20P}{100} $$
$$ = \frac{68P}{100} $$
Given total interest:
$$ \frac{68P}{100} = 4760 $$
$$ 68P = 476000 $$
$$ P = \frac{476000}{68} $$
$$ P = 7000 $$
Therefore, Karan borrowed:
$$ \boxed{₹7000} $$

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