Red, blue, green balls are in ratio 2:3:5. If 15 red, 10 blue, unknown green are added, ratio becomes 3:4:6. Green balls added?

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Accepted Answer

1. Let the initial counts be $2k,3k,5k$. After adding, counts are $2k+15,\;3k+10,\;5k+x$ and these are in ratio $3:4:6$.

2. So there is $t$ with $2k+15=3t$ and $3k+10=4t$. Solve: $\dfrac{3t-15}{2}=\dfrac{4t-10}{3}$, giving $t=25$ and $k=30$.

3. Use $5k+x=6t$: $150+x=150$, so $x=0$.

4. No green balls were added.

FINAL_ANSWER: d

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