What is the average of all three-digit numbers divisible by 19?

Question

Accepted Answer

1. Find first and last 3-digit multiples of 19: $19	imes6=114$ and $19	imes52=988$.
2. Count the terms: $n=\frac{988-114}{19}+1=47$.
3. Average of an AP is $(	ext{first} + 	ext{last})/2$. So average = $\frac{114+988}{2}=551$.

FINAL_ANSWER: c

Answer

Answer

Answer