Two containers of same volume are 35% and 60% full of water respectively. Then completely filled with milk. After mixing in larger vessel, what % is milk?

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**Solution**

1. Let each container have volume $V$. 
2. Milk added in first = $V-0.35V=0.65V$. In second = $V-0.60V=0.40V$. 
3. Total milk = $0.65V+0.40V=1.05V$. Total volume = $2V$. 
4. Milk percentage = $\dfrac{1.05V}{2V}	imes100\%=52.5\%$.

FINAL_ANSWER: c

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