Simplify:

$$
\left(2.5 + \frac{5}{8} ight)^2 - \left(\frac{7}{4} imes 2.4 ight)
$$

Question

Simplify:

$$
\left(2.5 + \frac{5}{8}ight)^2 - \left(\frac{7}{4} 	imes 2.4ight)
$$

Accepted Answer

Solution:
Given expression:
$$ \left(2.5 + \frac{5}{8}ight)^2 - \left(\frac{7}{4} 	imes 2.4ight) $$
First convert:
$$ 2.5 = \frac{5}{2} $$
So,
$$ \left(\frac{5}{2} + \frac{5}{8}ight)^2 - \left(\frac{7}{4} 	imes 2.4ight) $$
Now take LCM in the first bracket:
$$ \frac{5}{2} = \frac{20}{8} $$
Therefore,
$$ \frac{20}{8} + \frac{5}{8} = \frac{25}{8} $$
So the expression becomes:
$$ \left(\frac{25}{8}ight)^2 - \left(\frac{7}{4} 	imes 2.4ight) $$
Now square the first term:
$$ \left(\frac{25}{8}ight)^2 = \frac{625}{64} $$
$$ \frac{625}{64} = 9.765625 $$
Now solve the second bracket:
$$ \frac{7}{4} 	imes 2.4 $$
$$ = 1.75 	imes 2.4 $$
$$ = 4.2 $$
Now subtract:
$$ 9.765625 - 4.2 = 5.565625 $$
Rounding to four decimal places:
$$ 5.5656 $$
Therefore, the value of the expression is:
$$ \boxed{5.5656} $$
Final Answer: **5.5656**

Answer

Answer

Answer