If (A = 1, B = 2, … Z = 26) DOG :
4×15×7 :: CAT : ?

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Accepted Answer

1. Map the letters: $D=4$, $O=15$, $G=7$. So DOG is $4	imes15	imes7$.
2. For CAT: $C=3$, $A=1$, $T=20$.
3. So CAT is $3	imes1	imes20$, which matches option **(a)**.
FINAL_ANSWER: a

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Answer

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