A person cycles from home to work at a speed of 8 km/h and reaches 18 minutes late. If he increases his speed to 12 km/h, he reaches 6 minutes early. What is the distance (in km) from home to work?

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Accepted Answer

1. Let distance be $d$ km and scheduled time be $T$ hours.

2. From the given speeds: $\frac{d}{8}=T+0.3$ (18 min late) and $\frac{d}{12}=T-0.1$ (6 min early).

3. Subtract the equations: $\frac{d}{8}-\frac{d}{12}=0.4\Rightarrow\frac{d}{24}=0.4$.

4. Solve: $d=24	imes0.4=9.6$ km.

FINAL_ANSWER: b

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