What is the area of the segment formed by a chord in a circle of radius 10 cm, if the angle subtended at the center is 90°?

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Accepted Answer

1. Angle in radians: $	heta=90^\circ=	frac{\pi}{2}$. 
2. Sector area: $	frac{1}{2}r^2	heta=	frac{1}{2}\cdot10^2\cdot	frac{\pi}{2}=25\pi$. 
3. Triangle area (isosceles right): $	frac{1}{2}r^2\sin	heta=	frac{1}{2}\cdot10^2\cdot1=50$. 
4. Segment area = sector − triangle = $25\pi-50$.

FINAL_ANSWER: d

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