If base perimeter = 48 cm and slant height = 12 cm, what is the lateral surface area of a square pyramid?

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1. **Formula:** Lateral surface area = $\frac{1}{2}	imes	ext{perimeter}	imes	ext{slant height}$. 
2. Plug values: $	ext{LSA} = \frac{1}{2}	imes 48	imes 12$. 
3. Compute: $\frac{1}{2}	imes48 = 24$, and $24	imes12 = 288$. 
4. So the lateral surface area is $288	ext{ cm}^2$.

FINAL_ANSWER: a

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