A chord in a circle with radius 12 cm subtends an angle of 120° at the center. What is the area of the minor segment?

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1. **Sector area:** The sector with angle $120^\circ$ is $\frac{120}{360}=\frac{1}{3}$ of the circle. Area $=	frac{1}{3}\pi r^2=	frac{1}{3}\pi(12)^2=48\pi$.  
2. **Triangle area:** The triangle formed by the two radii has area $	frac{1}{2}r^2\sin120^\circ=	frac{1}{2}\cdot144\cdot\sin120^\circ=72\cdot	frac{\sqrt3}{2}=36\sqrt3$.  
3. **Segment area:** Sector minus triangle $=48\pi-36\sqrt3$. So the correct choice is (a).  
FINAL_ANSWER: <a>

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