In a circle PM and QN intersect at point O. If PM = 15 cm, find the length of OM.

Question

Accepted Answer

1. Given: $PM=15$ cm.

2. The problem note gives the ratio $OM:PM=1:3$.

3. So $OM=	frac{1}{3}	imes PM=	frac{1}{3}	imes15=15/3=5$ cm.

4. Thus $OM=5$ cm, which is option **(c)**.

FINAL_ANSWER: c

Answer

Answer

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