A circle of radius 12 cm has a sector with a central angle of 90°. Find the area of the minor segment formed by the chord of this sector. (𝜋 = 3.14)

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1. **Sector area:** Use $A=\frac12 r^2 	heta$ with $	heta=90^\circ=\frac{\pi}{2}$. So $A_{	ext{sector}}=\frac12\cdot12^2\cdot\frac{\pi}{2}=36\pi=113.04$. 
2. **Triangle area:** The triangle made by the two radii is right. Its area is $A_{	ext{tri}}=\frac12	imes12	imes12=72$. 
3. **Segment area:** Subtract sector minus triangle: $113.04-72=41.04\ 	ext{cm}^2$. 
FINAL_ANSWER: a

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