A right-angled triangle ABC (∠𝐵 = 90∘) has sides AB = 8 cm and BC = 15 cm. A perpendicular BD is dropped onto the hypotenuse AC. Find the length of AD.

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**Steps:**

1. Compute the hypotenuse: $AC=\sqrt{8^2+15^2}=\sqrt{289}=17$.
2. In a right triangle with altitude to the hypotenuse, use $AD=\frac{AB^2}{AC}$.
3. Substitute values: $AD=\frac{8^2}{17}=\frac{64}{17}\approx 3.76	ext{ cm}$.
4. So the correct choice is (a).

FINAL_ANSWER: a

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