If cosθ = 5/13 and θ lies in the first quadrant, find the value of sinθ.

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Accepted Answer

1. Use the identity: $\sin^2	heta + \cos^2	heta = 1$.

2. Plug $\cos	heta=5/13$: $\sin^2	heta = 1 - (5/13)^2 = 1 - 25/169 = 144/169$.

3. In the first quadrant, $\sin	heta$ is positive. So $\sin	heta = \sqrt{144/169} = 12/13$.

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