A sector of a circle subtends an angle of 90° at the centre and has radius 6 cm. Another sector of the same circle subtends an angle of π/2 radians. Find the ratio of the areas of the two sectors.

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Accepted Answer

1. Convert the angle: $90^\circ=\pi/2$ radians.

2. Area formula for a sector: $A=	frac{1}{2}r^2	heta$, where $	heta$ is in radians.

3. Both sectors have the same radius $r=6$ and the same angle $	heta=\pi/2$, so their areas are equal.

4. Thus the ratio of areas is **1 : 1**.

FINAL_ANSWER: c

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