A sum of ₹12000 is divided into two parts and lent at 6% and 11% simple interest respectively. If the total annual interest earned is ₹960, find the amount lent at 11%.

Question

Accepted Answer

1. Let the amount at 11% be $x$ and the other part be $12000-x$.

2. Total interest: $0.11x+0.06(12000-x)=960$.

3. Solve: $0.05x+720=960\Rightarrow0.05x=240\Rightarrow x=4800$.

4. So the amount lent at 11% is ₹4800.

FINAL_ANSWER: b

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