X was born three years after Y and Z got married. Y is three years younger than Z. Currently, X is 20 years younger than Y. Three years from now, the ratio of Z's age to Y's age will be $11 : 10$. How many years ago did Y and Z get married?

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**Solution:**

1. Let the present age of Z be $z$ years.
2. Since Y is 3 years younger than Z, Y's present age is $z - 3$.
3. X was born 3 years after Y and Z married. Let the number of years since marriage be $m$. Then, X's present age is $m - 3$ (because X was born 3 years after marriage, so X's age = time since marriage minus 3).
4. Given that X is 20 years younger than Y:
   $$m - 3 = (z - 3) - 20$$
   Simplifying:
   $$m - 3 = z - 23$$
   $$m = z - 20$$

5. After 3 years, the ratio of Z's age to Y's age will be $11 : 10$:
   $$\frac{z + 3}{(z - 3) + 3} = \frac{11}{10}$$
   Simplify denominator:
   $$(z + 3) / z = 11 / 10$$

6. Cross-multiplied:
   $$10(z + 3) = 11z$$
   $$10z + 30 = 11z$$
   $$30 = 11z - 10z = z$$

7. So, $z = 30$ years.
8. From step 4, $m = z - 20 = 30 - 20 = 10$ years.

Therefore, Y and Z got married 10 years ago.

**Answer:** 10 years

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