Working for 10 hours per day, 6 men can build a wall in a certain number of days. By working for how many hours/minutes per day can 12 men build the wall in the same number of days?

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Accepted Answer

**Solution:**

1. The total work done is constant and equals the product of the number of men, hours per day, and number of days.

2. Since the number of days is the same, the product of men and hours per day remains constant:

$$M_1 	imes H_1 = M_2 	imes H_2$$

3. Given:
   - Initial men, $M_1 = 6$
   - Initial hours per day, $H_1 = 10$
   - New men, $M_2 = 12$
   - New hours per day, $H_2 = ?$

4. Substitute the values:

$$6 	imes 10 = 12 	imes H_2$$

$$60 = 12 	imes H_2$$

5. Solve for $H_2$:

$$H_2 = \frac{60}{12} = 5$$

**Answer:** The 12 men need to work for **5 hours** per day to complete the work in the same number of days.

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