Find the coordinates of the points where the graph of the equation $$57x - 19y = 399$$ cuts the coordinate axes.

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**Solution:**

1. To find the x-intercept, set $y = 0$ in the equation:
   $$57x - 19(0) = 399 \implies 57x = 399 \implies x = \frac{399}{57} = 7$$
   So, the x-intercept is at $(7, 0)$.

2. To find the y-intercept, set $x = 0$ in the equation:
   $$57(0) - 19y = 399 \implies -19y = 399 \implies y = \frac{399}{-19} = -21$$
   So, the y-intercept is at $(0, -21)$.

**Answer:** The graph cuts the x-axis at $(7, 0)$ and the y-axis at $(0, -21)$.

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