A and B can complete a work together in 48 days. A is 4 times as work efficient as B. In how many days can B alone complete the work?

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Accepted Answer

**Solution:**

1. Let the efficiency of B be *x* units of work per day. Then efficiency of A is *4x* units per day.

2. Together, A and B complete *4x + x = 5x* units of work per day.

3. They complete the entire work in 48 days, so total work = *48 	imes 5x = 240x* units.

4. Since B alone works at *x* units per day, the time taken by B alone to complete the work is:
   $$\frac{	ext{Total work}}{	ext{B's efficiency}} = \frac{240x}{x} = 240 	ext{ days}$$

**Answer:** 240 days

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