There are 4 friends A, B, C, and D standing in a straight line, though not necessarily in the same order. A and B are ahead of at least 1 person. B stands between C and D. D does not stand last. Who stands first?

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**Solution:**

1. Given that A and B are ahead of at least one person, neither A nor B can be last.

2. B stands between C and D, so B cannot be first or last.

3. D does not stand last, so the last position must be occupied by C.

4. Since B is between C and D, and C is last (4th position), B must be 2nd and D must be 3rd.

5. The only remaining position is 1st, which must be occupied by A.

**Final arrangement:** A (1st), B (2nd), D (3rd), C (4th).

**Answer:** A stands first.

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