The induced current in a coil is the highest when the direction of motion of the coil is at what angle relative to the magnetic field?

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**Solution:**

1. The induced current in a coil is generated by a change in magnetic flux through the coil.

2. The magnetic flux is given by $$\Phi = B \cdot A \cdot \cos(	heta)$$, where:
   - $B$ is the magnetic field strength,
   - $A$ is the area of the coil,
   - $	heta$ is the angle between the magnetic field and the normal to the coil.

3. The rate of change of magnetic flux induces an electromotive force (EMF) and hence current.

4. The force on a wire carrying current in a magnetic field is:
   $$F = BIL \sin(	heta)$$
   where $	heta$ is the angle between the current direction and magnetic field.

5. The force (and thus induced current) is maximized when $\sin(	heta) = 1$, i.e., when $	heta = 90^\circ$.

6. Therefore, the induced current is highest when the coil moves at right angles to the magnetic field.

**Answer:** at right angles to the magnetic field

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