Two numbers are, respectively, 10\% and 25\% more than the third number. What is the ratio of the two numbers?

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**Solution:**

1. Let the third number be *p*.

2. The first number *A* is 10\% more than *p*:
   $$A = p + 10\% \times p = p + \frac{10}{100}p = \frac{110}{100}p = \frac{11p}{10}$$

3. The second number *B* is 25\% more than *p*:
   $$B = p + 25\% \times p = p + \frac{25}{100}p = \frac{125}{100}p = \frac{5p}{4}$$

4. Find the ratio $ A : B $:
   $$\frac{A}{B} = \frac{\frac{11p}{10}}{\frac{5p}{4}} = \frac{11p}{10} \times \frac{4}{5p} = \frac{11 \times 4}{10 \times 5} = \frac{44}{50} = \frac{22}{25}$$

**Answer:** The ratio of the two numbers is $22 : 25$.

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